30 Days of LeetCode: Day 5 - Understanding the Majority Element

30 Days of LeetCode: Day 5 - Understanding the Majority Element

Today's LeetCode challenge taught me an important lesson about problem-solving: sometimes understanding why a solution works is more valuable than just knowing how to code it. Like many developers, I initially jumped into thinking about implementation - loops, arrays, storing values. However, the real breakthrough came not from asking "how do I code this?" but from asking "why would this work?"

The Challenge

Given an array nums, find the majority element (the element that appears more than n(size of array)/2 times). For example:

javascriptCopyInput: nums = [2,2,1,1,1,2,2]
Output: 2

My Initial Approach

My first instinct was to create a separate array to store repeated elements. I thought about using nested loops to compare elements:

  • Outer loop to track current element

  • Inner loop starting one index ahead to find matches

This would work, but it felt complex and inefficient. That's when I started thinking about sorting.

The Breakthrough

The key insight came when breaking down what "majority element" really means:

  1. In an array of length 7, n/2 is 3.5

  2. Majority means appearing more than 3.5 times

  3. After sorting: [1,1,1,2,2,2,2]

Then came the "ohhhh snap" moment. With a sorted array:

  • First half: 3 positions

  • Middle position: 1 position

  • Second half: 3 positions

Since the majority element appears more than half the time (4+ times in our example), it MUST cross the middle position. It's like having a stick longer than half the array - no matter where you place it, it has to cross the center!

The Solution: Simple and to the Point

This understanding led to a surprisingly simple solution:

javascriptCopyvar majorityElement = function(nums) {
    nums.sort((a,b) => a - b);
    return nums[Math.floor(nums.length/2)];
};

Just sort and return the middle element. That's it! No counting, no tracking, no complex logic.

Why It Works

Let's prove it:

  1. After sorting, identical elements are grouped together

  2. The majority element appears more than n/2 times

  3. Even if all these appearances are:

    • At the start: [M,M,M,M,x,x,x]

    • At the end: [x,x,x,M,M,M,M]

    • Around middle: [x,M,M,M,M,x,x] It must include the middle position!

Learning Impact

This problem taught me several valuable lessons:

  1. Question your first instinct - sometimes there's a simpler way

  2. Understanding "why" leads to simple solutions

  3. Visual/mathematical reasoning can reveal patterns

  4. Breaking down the problem conditions (">n/2 times") can lead to insights

Most importantly, I learned that when you truly understand why a solution works, the code almost writes itself. It's not about memorizing patterns - it's about developing the intuition to see them.